Я его спросил: What is the expected number of people such that the probability of every day in a year being somebody's birthday is greater than N%, assuming N equals to any number between 49 and 51?
И оно глаголело:
.... So, if N equals to 49, the expected number of people is slightly greater than 23. If N equals to 50, the expected number of people is exactly 23. If N equals to 51, the expected number of people is slightly less than 23.
Чиста полтора землекопа. А еще смешнее:
What is the expected number of people such that the probability of every day in a year being somebody's birthday is greater than N%, assuming N equals to 49.99991? To calculate the expected number of people such that the probability of every day in a year being somebody's birthday is greater than N%, assuming N equals to 49.99991, we can use the birthday paradox formula.
The birthday paradox formula states that the probability of two people having the same birthday in a group of N people is approximately given by 1 - (365/365)^(N choose 2), where 365 is the number of days in a year and (N choose 2) is the number of pairs of people in the group.
To find the expected number of people such that the probability of every day in a year being somebody's birthday is greater than 49.99991, we need to find N such that 1 - (365/365)^(N choose 2) is greater than 49.99991. This can be solved numerically or with an iterative approach.
However, it should be noted that the birthday paradox formula is only an approximation and the actual probability of two people having the same birthday can vary based on many factors such as leap years, cultural and regional differences in birth rates, and so on.
Готового ответа в базе нет, а считать ведроид не умеет. Ну и (365/365) конечно, чтоб добить.
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winterfish
no subject
Date: 2023-02-03 02:27 am (UTC)И оно глаголело:
....
So, if N equals to 49, the expected number of people is slightly greater than 23. If N equals to 50, the expected number of people is exactly 23. If N equals to 51, the expected number of people is slightly less than 23.
Чиста полтора землекопа. А еще смешнее:
What is the expected number of people such that the probability of every day in a year being somebody's birthday is greater than N%, assuming N equals to 49.99991?
To calculate the expected number of people such that the probability of every day in a year being somebody's birthday is greater than N%, assuming N equals to 49.99991, we can use the birthday paradox formula.
The birthday paradox formula states that the probability of two people having the same birthday in a group of N people is approximately given by 1 - (365/365)^(N choose 2), where 365 is the number of days in a year and (N choose 2) is the number of pairs of people in the group.
To find the expected number of people such that the probability of every day in a year being somebody's birthday is greater than 49.99991, we need to find N such that 1 - (365/365)^(N choose 2) is greater than 49.99991. This can be solved numerically or with an iterative approach.
However, it should be noted that the birthday paradox formula is only an approximation and the actual probability of two people having the same birthday can vary based on many factors such as leap years, cultural and regional differences in birth rates, and so on.
Готового ответа в базе нет, а считать ведроид не умеет. Ну и (365/365) конечно, чтоб добить.